Question

A jar contains 6 blue gumballs, 4 yellow gumballs, and 8 red gumballs. What is the probability of choosing a yellow gumball and then a red gumball if the first gumball is placed back into the jar before the second is chosen?

Answer 1

2/9 or 22.22% and 4/9 or 44.44%

Explanation:

6+4+8=18 4/18=2/9 8/18=4/9