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Answer:
A. 0 = −(x−6)^2+12
Explanation:
The vertex form of a quadratic equation is ...
y = a(x -h)² +k . . . . . . for vertex (h, k) and scale factor 'a'
When the given vertex (h, k) = (6, 12) is used, we find the form of the equation to be ...
y = a(x -6)² +12
The ball will be on the ground when y = 0. Here, the vertical scale factor 'a' is -1, so the equation representing the ball being on the ground is ...
0 = -(x -6)² +12 . . . . . . matches choice A