Evaluate p+(n-1) x3 for n=7 and p=9

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asked Apr 19, 2022 150k views

1 Answer

Starlight · Answer 1 · 2022-04-24T23:41:36+0000

is x3 an exponent ? i answered one of ur earlier questions and i assumed x3 was multiplication

9 + (7 - 1)^3
= 9 + (6)^3
= 9 + (216)
= 225

or if it is multiplication...

then the answer is 27

Evaluate p+(n-1) x3 for n=7 and p=9

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