Question

A 40.0 liter gas tank contains 70.0 moles of hydrogen gas. What would be the volume of the tank which could hold 50.0 moles of hydrogen gas at the same temperature and pressure

Answer 1

`V_2=28.6L`

Step-by-step explanation:

Hello there!

In this case, according to the given information, it is possible for us to solve this problem via the Avogadro's gas law as a way to understand the volume-moles behavior as a directly proportional relationship:

`(V_2)/(n_2)=(V_1)/(n_1)`

In such a way, we solve for the final volume as shown below:

`V_2=(V_1n_2)/(n_1) \\\\V_2=(40.0L*50.0mol)/(70.0mol)\\\\V_2=28.6L`

Regards!