Question

A 116 watt LED light bulb has a current of 11 amperes running through it. What is the

voltage in the lightbulb?

Answer 1

Voltage = 10.54545

Given -

Current (I) - 11

Amps - 11

Resistance - 0.95868

Power - 116

We can conclude:

The voltage will be 10.54545, because of Ohm's Law:

Ohm's law states that:

Voltage (V) = Current (I) * Resistance (R)

Power (P) = Voltage (V) * Current (I)