Answer:
a, a + 1, a + 2
55, 56. 57
Explanation:
Let the integers be :
a, a + 1, a + 2 (consecutive integers)
Hence, sum of the integers equals 168
a + (a + 1) + (a + 2) = 168
a + a + 1 + a + 2 = 168
3a + 3 = 168
3a = 168 - 3
3a = 165
a = 165 / 3
a = 55
first integer, a = 55
Second, a +1 = 56
Third, a + 2 = 57