Question

A thermometer reads a pressure of 120 kPa at 0 ˚C. What is the temperature when the thermometer reads a pressure of 80 kPa? (Celsius + 273 = Kelvin) Use Gay Lussac's Formula to solve. 182 K 192 K 202 K 212 K

Answer 1

T₂ = 182 K

Step-by-step explanation:

Given that,

Initial pressure, P₁ = 120 kPa

Initial temperature, T₁ = 0˚C = 273 K

We need to find the final temperature when the pressure is 80 kPa.

We know that, Gay Lussac's Formula is :

`(P_1)/(T_1)=(P_2)/(T_2)\\\\T_2=(P_2T_1)/(P_1)\\\\T_2=(80\ kPa* 273)/(120\ kPa)\\\\T_2=182\ K`

So, the new temperature is equal to 182 K.