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(sin 9x)'
what is the derivative of sin 9x​

User Tom McLean
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1 Answer

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Answer:


\displaystyle (d)/(dx)[\sin(9x)] = 9 \cos(9x)

General Formulas and Concepts:

Calculus

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:
\displaystyle (d)/(dx) [cf(x)] = c \cdot f'(x)

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
\displaystyle (d)/(dx)[f(g(x))] =f'(g(x)) \cdot g'(x)

Explanation:

Step 1: Define

Identify


\displaystyle y = \sin(9x)

Step 2: Differentiate

  1. Trigonometric Differentiation [Derivative Rule - Chain Rule]:
    \displaystyle y' = \cos(9x)(9x)'
  2. Rewrite [Derivative Property - Multiplied Constant]:
    \displaystyle y' = 9 \cos(9x)(x)'
  3. Basic Power Rule:
    \displaystyle y' = 9 \cos(9x)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

User Laquan
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