Question

Write the standard form of the equation of the circle with the graph shown to the right.

Answer 1

(x+5)²+(y+5)² =4

Explanation:

the standard equation is

(x-h)²+(y-k)²=r²

where (h, k) is the center in our case ( -5, -5) and r is the radius that in our case r=2, so substitute

(x+5)²+(y+5)²=2²

Answer 2

`(x+5)^2+(y+5)^2=4`

Explanation:

Hi there!

Equation of a circle:
`(x-h)^2+(y-k)^2=r^2` where the circle is centered at (h,k) and r is the radius

1) Determine the center of the circle

On the graph, we can determine that the circle is centered at the point (-5,-5). Plug this into the equation:

`(x-(-5))^2+(y-(-5))^2=r^2\\(x+5)^2+(y+5)^2=r^2`

2) Determine the value of r²

In the graph, we can see that the radius of the circle is equal to 2 units. Therefore, the value of r² is 4. Plug this back into the equation:

`(x+5)^2+(y+5)^2=4`

I hope this helps!