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The energy of an object can be converted to heat due to the friction of the car on the hill. The difference between the potential energy of the car and its kinetic energy at the bottom of the hill equals the energy lost due... (i need help rn lol)

User TheJeff
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2 Answers

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Final answer:

Physics concepts such as potential energy, kinetic energy, and the conservation of energy are applied to a scenario where a car moves up and down a hill. Energy is converted from chemical to potential and then to kinetic, with some loss to heat through friction, particularly when braking.

Step-by-step explanation:

The energy transformations involved in the scenario of a car moving up and down a hill and coming to a rest involves several physics concepts including potential energy, kinetic energy, and the conservation of energy. As the car climbs a mountain, it converts the chemical energy of the fuel into gravitational potential energy. While descending, this potential energy is converted back into kinetic energy, which in turn can be lost as heat due to friction, especially when the car uses its brakes. When the car's kinetic energy changes due to direction or speed, work is being done, and this work can be expressed in joules.

According to the law of conservation of energy, in a closed system, the total mechanical energy (potential energy plus kinetic energy) remains constant, assuming no energy is lost to the surroundings. If friction is not negligible, as in this scenario, some of the mechanical energy is indeed lost as heat due to friction, particularly in the brakes, which can become very hot.

When applying these principles to a car on a hill, several energy transformations occur. Initially, chemical energy is used to increase the car's potential energy; as it moves downhill, that potential energy is converted into kinetic energy. If the car brakes, some kinetic energy is transformed into heat through friction. These processes illustrate the conversion between different forms of energy and the practical effects such as heating due to friction.

User Pegolon
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1 vote

Answer:

Energy Lost for group A's car = 0.687 J

Energy Lost for group B's car = 0.55 J

Step-by-step explanation:

The exact question is as follows :

Given - The energy of an object can be converted to heat due to the friction of the car on the hill. The difference between the potential energy of the car and its kinetic energy at the bottom of the hill equals the energy lost due to friction.

To find - How much energy is lost due to heat for group A's car ?

How much for Group B's car ?

Solution -

We know that,

GPE = 1 Joule (Potential Energy)

Now,

For Group A -

Energy Lost = GPE - KE

= 1 J - 0.313 J

= 0.687 J

So,

Energy Lost for group A's car = 0.687 J

Now,

For Group B -

Energy Lost = GPE - KE

= 1 J - 0.45 J

= 0.55 J

So,

Energy Lost for group B's car = 0.55 J

The energy of an object can be converted to heat due to the friction of the car on-example-1
The energy of an object can be converted to heat due to the friction of the car on-example-2
User ShujatAli
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