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The venticles of a right angle are a[0,4], b[3,-2] c[-3, -4] Find It's area.​

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Answer:

The area of this triangle is about 21.2132 square units.

Explanation:

First, find the lengths of the legs AB and BC.

Length of AB ===

Find the difference in position vertically:


-2-4=-6

The points are 6 units apart vertically.

Find the difference in position horizontally:


3-0=3

The points are 3 units apart horizontally.

These lengths form a right triangle with the distance between the points as the hypotenuse, so you can use the pythagorean theorem to solve:


a^2+b^2=c^2\\3^2+6^2=c^2\\9+36=c^2\\45=c^2\\c\approx6.7082

AB is about 6.7082 units long.

Length of BC ===

Same process as above.

Find the vertical distance:


-4--2=-2

2 units apart vertically.

Find the horizontal distance:


-3-3=-6

6 units apart horizontally.

Use the pythagorean theorem:


2^2+6^2=c^2\\4+36=c^2\\40=c^2\\c=6.3246

BC is about 6.3246 units long.

Area ===

Finally, you can use these to find the area of the triangle. The area of a right triangle is just half the area of a rectangle with the same base and height:


A=(b* h)/(2)\\\\A=(6.7082*6.3246)/(2)\\\\A=(42.4264)/(2)\\\\A=21.2132

The area of this triangle is about 21.2132 square units.

The venticles of a right angle are a[0,4], b[3,-2] c[-3, -4] Find It's area.​-example-1
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