Answer:
2/15 ; 6/15 ; 1/5
Explanation:
Number on spinner = (2, 3, 5)
Number on card = (1, 1, 2, 3, 4)
____ 2 ___ 3 ____ 5
1__1, 2 __ 1, 3 ___1, 5
1__1, 2 __ 1, 3 ___1, 5
2_ 2,2___2,3 ___2,5
3_ 3,2 __ 3,3 ___3,5
4_ 4,2 __ 4,3 ___4,5
1.)
To get a difference of 0:
{(2,2) ; (3,3)} = 2
Total possible outcomes = sample space = 15
P(difference of 0) = 2 / 15
2.)
Product of 2 resulting numbers is odd:
{(1,3) ; (1,5) ; (1,3) ; (1,5) ; (3,3) ; (3,5)} = 6
Total possible outcomes = 15
P(product is odd) = 6 /15
3.)
Product is atleast 12 :
{(3,5) ; (4,3) ; (4,5)} = 3
Total possible outcomes = 15
P(product is atleast 12) = 3/15 = 1/5