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Find the pH of 2.1 x 10-3 [HCI]
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Find the pH of
2.1 x 10-3 [HCI]

User Bledi
by
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1 Answer

5 votes

Answer: pH = 2.68

Explanation: pH = - log[H3O^+] .

HCl reacts with water : HCl + H2O -> Cl^- + H3O^+

So [H3O^+] = c(HCl) = 0.0021 M

pH = - log(0.0021) = 2.68

User Jarek Tkaczyk
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