Light of wavelength 633 nm from a He-Ne laser passes through a circular aperture and is observed on a screen 4.0 m behind the aperture. The diameter of the central bright area is 5.4 cm. What is the diameter

asked Feb 28, 2022 138k views

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5 votes

Answer:

The answer is "
$1.144 * 10^(-4) \ m$ ".

Step-by-step explanation:

$w=(2.44 \lambda L)/(D)\\\\D=(2.44 \lambda L)/(w)\\\\$

$=(2.44 * 633 * 10^(-9)* 4 )/(0.054)\\\\=(6178.08* 10^(-9))/(0.054)\\\\=1.144 * 10^(-4) \ m$

Sudocracy answered Mar 6, 2022

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