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A political poll finds that 305 out of 600 (50.8%) of a random sample of likely voters are in favor of the Democrat over the Republican prior to a recent local election between the two candidates. The p-value from a two-sided test of whether the population proportion is different than 50% is 0.714.

1. Which of the following could be the correct 95% confidence interval (range of plausible values) for the true proportion of voters that will vote for the Democrat candidate?

a. (46.8%, 54.8%)
b. (50.1%, 58.0%)
c. (53.0%, 61.0%)

2. When should you use the median as a summary statistic instead of the mean?

User Egghese
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1 Answer

4 votes

Answer:

1)

Option A.(46.8%, 54.8%) is the correct Answer.

Since the Confidence Interval for the true proportion must contain or include ( p = 50% or 0.5 ), (46.8%, 54.8%) could be the correct 95% confidence interval (range of plausible values) for the true proportion of voters that will vote for the Democrat candidate.

2)

When a graph falls on a normal distribution, Using the mean is very good choice but when the data has extreme scores, then one should use the median instead of the mean.

Explanation:

Given the data in the question;

Null hypothesis H₀ : p = 50% or 0.5

Alternative hypothesis Hₐ : p ≠ 50% or 0.5

given that p-value = 0.714

The p-value is large, so we can not reject Null hypothesis.

Thus, p = 50% or 0.5

Meaning that, the Confidence Interval for the true proportion must contain or include ( p = 50% or 0.5 )

Thus, Option A.(46.8%, 54.8%) is the correct Answer.

Since the Confidence Interval for the true proportion must contain or include ( p = 50% or 0.5 ), (46.8%, 54.8%) could be the correct 95% confidence interval (range of plausible values) for the true proportion of voters that will vote for the Democrat candidate.

2)

When a graph falls on a normal distribution, Using the mean is very good choice but when the data has extreme scores, then one should use the median instead of the mean.

User Hacer
by
5.5k points