Question

Suppose that you wish to construct a simple AC generator with an output of 12 V maximum when rotated at 60 Hz. A magnetic field of 0.050 T is available. If the area of the rotating coil is 100 cm2, how many turns are needed?

Answer 1

N = 63.6

Step-by-step explanation:

The emf induced in AC generator is given as follows:

`V = N\omega AB Sin\theta`

for maximum output,
`Sin\theta = 1`

`V = N(2\pi f) AB`

where,

V = Maximum Output Voltage = 12 V

N = No. of Turns = ?

f = frequency = 60 Hz

A = Area of Coil = 100 cm² = 0.01 m²

B = Strength of Magnetic Field = 0.05 T

Therefore,

`12\ V = N(2)(\pi)(60\ Hz)(0.01\ m^2)(0.05\ T)\\\\N = (12\ V)/((2)(\pi)(60\ Hz)(0.01\ m^2)(0.05\ T))`

N = 63.6