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The Regency Hotel has enough space at its entrance for six taxicabs to line up, wait for guests, and then load passengers. Cabs arrive at the hotel every 8 minutes; if a taxi drives by the hotel and the line is full, it must drive on. Hotel guests require a taxi every 5 minutes, on average. It takes a cab driver an average of 3.5 minutes to load passengers and luggage and leave the hotel(exponentially distributed).

1. What is the average time a cab must wait for a fare?
2. What is the probability that the line will be full when a cab drives by, causing it to drive on?

User Alokraop
by
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1 Answer

5 votes
5 votes

Answer:

The appropriate solution is:

(1) 22.81 minutes

(2) 0.171

Explanation:

According to the question, the values will be:

The service rate of guess will be:

=
5+3.5

=
8.5 \ minutes

The mean arrival rate will be:


\lambda =(60)/(5)


=7.5 \ cabs/hr

The mean service rate will be:


\mu= 7.05 \ cabs/hr

(1)

The average time a cab must wait will be:


W_q=22.95-(1)/(7.05)


=(161.798-1)/(7.05)


=(160.798)/(7.05)


=22.81 \ minutes

(2)

The required probability will be:


P(X\geq 6)=(1-2.115)/(1-7.5)


=(-1.1115)/(-6.5)


=0.171

User MEX
by
3.0k points