Question

A diving board 3.00 m long is supported at a point 1.00 m from the end, and a diver weighing 500 N stands at the free end. The diving board is of uniform cross section and weighs 280 N. Find:

a. the force at the support point
b. the force at the left-hand end.

Answer 1

`F_l=1140N`

Step-by-step explanation:

From the question we are told that:

Length
`l=3.00m`

Support distance
`d=1.00m`

Weight of diver
`W_d=500N`

Weight of board
`W_b=280N`

Generally the equation for Total Torque is mathematically given by

`F_T=W_d-W_b`

`F_T=F_d-f_b`

`F_T=-280-500`

`F_T=-780`

`F_T=780`

Since we consider the horizontal axis

`\sum Y=0`

`Fs-((1)/(2)l*w_b)-(l-w_d)`

`Fs-1.5*280-3*300=0`

`F_s=1920N`

Therefore the force at the support point 1.00m from the force at the left-hand

`F_l=F_s-F_l`

`F_l=1920-780`

`F_l=1140N`