Answer:
Part A:
Since the calculated value of z falls in the critical region we conclude that there has been a significant increase in the mean number of arrivals per hour at 0.025 significance level.
Part B:
The calculated value of z =2.73 falls in the critical region we conclude that there has been a significant increase in the mean number of arrivals per hour at 0.01 significance level as well.
Part C:
We are assuming that the standard deviation of the population is equal to the standard deviation of the sample as n= 30 and it is a normal distribution.
Explanation:
The population mean = u= 195
The population standard deviation = σ= 14
The sample mean = x`= 202
The sample standard deviation = s=
Sample size = n= 30
Let the null and alternate hypotheses be
H0: u ≤ 195 against the claim Ha: u > 195
The significance level ∝= 0.025
Calculating z
z= x`-u/σ/√n
z= 202-195/14/√30
Z= 7/14/5.477
z= 7/2.556
z=2.73
Part A:
The critical region for Z∝= 0.025 is Z>1.96 for right tailed test
Since the calculated value of z falls in the critical region we conclude that there has been a significant increase in the mean number of arrivals per hour at 0.025 significance level.
Part B:
The critical region for Z∝= 0.01 is Z > 2.33 for right tailed test
The calculated value of z =2.73 falls in the critical region we conclude that there has been a significant increase in the mean number of arrivals per hour at 0.01 significance level as well.
Part C:
We are assuming that the standard deviation of the population is equal to the standard deviation of the sample as n= 30 and it is a normal distribution.