Answer:
![\displaystyle -√(3) - 2](https://img.qammunity.org/2023/formulas/mathematics/high-school/n2wnlhoodqixvh1bce57hz3fclwqvycz74.png)
Step-by-step explanation:
If you recall the unit circle [from the polar graph], you would have no trouble at all figuring this out, but sinse you have trouble, do not worry about it. So, here is what you should have realised:
![\displaystyle \boxed{1(1)/(2)\pi} = (18)/(12)\pi](https://img.qammunity.org/2023/formulas/mathematics/high-school/nbbuqua6rkqp4xc54nx842z219sdvjd6fw.png)
If you did not notise,
or
is just
more than
which means the exact value will either be a radical, followed by an integer or just a radical. In this case, accourding to the unit circle, you will have a radical, followed by an integer, and that will be this:
![\displaystyle (sin\:1(7)/(12)\pi)/(cos\: 1(7)/(12)\pi) = tan\:1(7)/(12)\pi \\ \\ \boxed{-√(3) - 2} = (sin\:1(7)/(12)\pi)/(cos\: 1(7)/(12)\pi)](https://img.qammunity.org/2023/formulas/mathematics/high-school/sc2mc4vd49gbhesd64eeawjwskj7h2cc2x.png)
It is all about memorisation of the unit circle, which I know is difficult, but you will get used to it soon.
*Now, if you had to find
then the exact value would be the OPPOCITE of the exact value of
which is
because you would be crossing into the second quadrant where the x-coordinates are negative, accourding to both the cartesian and polar graphs. In addition, sinse you ALREADY have both values for sine and cosine [accourding to your PREVIOUS QUESTION ASKED], all you need to do is divide both values in the order given above to arrive at the exact value for
![\displaystyle tan\:1(7)/(12)\pi.](https://img.qammunity.org/2023/formulas/mathematics/high-school/pqe4mksuaaa4ytwbv8qgqi2tx4erscg9p1.png)
I am joyous to assist you at any time.