Question

What is an equation of the line that passes through the points (-4,-3) and (3,-3)

Answer 1

y=-3

Explanation:

m=(y2-y1)/(x2-x1)

m=(-3-(-3))/(3-(-4))

m=(-3+3)/(3+4)

m=0/7

m=0

y-y1=m(x-x1)

y-(-3)=0(x-(-4))

y+3=0(x+4)

y+3=0

y=0-3

y=-3