Answer:
scale factor(k)=23
A(x,y)=A'(kx,ky)
Let's do by using this formula
C(9,0)=C'(kx,ky)(here x=9 and y=0)
C(9,0)=(23*9,23*0)
C(9,0)=(207,0)
A(0,3)=A'(kx,ky)(here x=0 and y=3)
A(0,3)=A'(23*0,23*3)
A(0,3)=A'(0,69)
Explanation:
sorry i dont know how to do B no