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1 vote
The curve


y = √(x - 3)
has a tangent with gradient

(1)/(2)
at point N.
Find the coordinates of N.​

1 Answer

3 votes

Answer:

Point N(4, 1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Algebra I

  • Coordinates (x, y)
  • Functions
  • Function Notation
  • Terms/Coefficients
  • Anything to the 0th power is 1
  • Exponential Rule [Rewrite]:
    \displaystyle b^(-m) = (1)/(b^m)
  • Exponential Rule [Root Rewrite]:
    \displaystyle \sqrt[n]{x} = x^{(1)/(n)}

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
\displaystyle (d)/(dx)[f(g(x))] =f'(g(x)) \cdot g'(x)

Explanation:

Step 1: Define


\displaystyle y = √(x - 3)


\displaystyle y' = (1)/(2)

Step 2: Differentiate

  1. [Function] Rewrite [Exponential Rule - Root Rewrite]:
    \displaystyle y = (x - 3)^{(1)/(2)}
  2. Chain Rule:
    \displaystyle y' = (d)/(dx)[(x - 3)^{(1)/(2)}] \cdot (d)/(dx)[x - 3]
  3. Basic Power Rule:
    \displaystyle y' = (1)/(2)(x - 3)^{(1)/(2) - 1} \cdot (1 \cdot x^(1 - 1) - 0)
  4. Simplify:
    \displaystyle y' = (1)/(2)(x - 3)^{-(1)/(2)} \cdot 1
  5. Multiply:
    \displaystyle y' = (1)/(2)(x - 3)^{-(1)/(2)}
  6. [Derivative] Rewrite [Exponential Rule - Rewrite]:
    \displaystyle y' = \frac{1}{2(x - 3)^{(1)/(2)}}
  7. [Derivative] Rewrite [Exponential Rule - Root Rewrite]:
    \displaystyle y' = (1)/(2√(x - 3))

Step 3: Solve

Find coordinates

x-coordinate

  1. Substitute in y' [Derivative]:
    \displaystyle (1)/(2) = (1)/(2√(x - 3))
  2. [Multiplication Property of Equality] Multiply 2 on both sides:
    \displaystyle 1 = (1)/(√(x - 3))
  3. [Multiplication Property of Equality] Multiply √(x - 3) on both sides:
    \displaystyle √(x - 3) = 1
  4. [Equality Property] Square both sides:
    \displaystyle x - 3 = 1
  5. [Addition Property of Equality] Add 3 on both sides:
    \displaystyle x = 4

y-coordinate

  1. Substitute in x [Function]:
    \displaystyle y = √(4 - 3)
  2. [√Radical] Subtract:
    \displaystyle y = √(1)
  3. [√Radical] Evaluate:
    \displaystyle y = 1

∴ Coordinates of Point N is (4, 1).

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

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