Question

Find the length of the side C in the triangle ABC where a=4.7 b=10.21 and ACB=105.3

Answer 1

9514 1404 393

Answer:

(d) 12.3

Explanation:

From the Law of Cosines, you can solve for c:

c = √(a² +b² -2ab·cos(C)) = √(22.09 +104.2441 -95.974cos(105.3°))

c ≈ √151.659 ≈ 12.31499

Side c is about 12.3 units long.