Question

5. 16.3 g of NaCl is dissolved in water to make 1.75 L of solution. What is the molarity of this solution? A 0.159 M B 0.278 M C 9.31 M D 33.4 M​

Answer 1

Answer: The molarity of this solution is 0.159 M.

Step-by-step explanation:

Given: Mass of solute = 16.3 g

Volume = 1.75 L

Number of moles is defined as the mass of substance divided by its molar mass.

Hence, moles of NaCl (molar mass = 58.44 g/mol) ar calculated as follows.

`Moles = (mass)/(molar mass)\\= (16.3 g)/(58.44 g/mol)\\= 0.278 mol`

Molarity is the number of moles of a substance present in a liter of solution.

So, molarity of the given solution is calculated as follows.

`Molarity = (no. of moles)/(Volume (in L))\\= (0.278 mol)/(1.75)\\= 0.159 M`

Thus, we can conclude that the molarity of this solution is 0.159 M.