Question

at what temperature will the mass of 198g of carbon dioxide gas at 2 atmospheric pressure take up to a volume of 35l? (gas constant= 0.0821L atm.​

Answer 1

The temperature will be 189.70 K.

Step-by-step explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

In this case:

• P= 2 atm
• V= 35 L
• n= 198 g*
  `(1 mole)/(44 g)` = 4.5 moles (where 44 g/mole is the molar mass of carbon dioxide)
• R= 0.082
  `(atm*L)/(mol*K)`
• T= ?

Replacing:

2 atm* 35 L= 4.5 moles* 0.082
`(atm*L)/(mol*K)` * T

Solving:

`T=(2 atm* 35 L)/(4.5 moles* 0.082(atm*L)/(mol*K) )`

T= 189.70 K

The temperature will be 189.70 K.