Question

I need help figuring out this question

Answer 1

nre, nre

Explanation:

Given

`4b^2 + 16 = 0`

Required

Solve

`4b^2 + 16 = 0`

Subtract 16 from both sides

`4b^2 +16 -16 = 0 - 16`

`4b^2 = - 16`

Divide both sides by 4

`b^2 = -4`

Take square roots of both sides

`b = \sqrt{-4`

`√(-4) \to` Complex number

Hence, no real root exist