Question

Us
If f(x) = x2, and
g(x) = x – 1, then
g(f(x)) = x[?] + [?]

Answer 1

`g(f(x)) = x^([2]) +[-1]`

Explanation:

Given

`f(x) = x^2`

`g(x) =x -1`

Required

`g(f(x))`

We have:

`g(x) =x -1`

Replace x with f(x):

`g(f(x)) = f(x) -1`

Substitute
`f(x) = x^2`

`g(f(x)) = x^2 -1`

Hence:

`g(f(x)) = x^([2]) +[-1]`