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Solve the following equation. log(3x)=log(2x-4) *
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3 votes
Solve the following equation. log(3x)=log(2x-4) *

User Robin McCorkell
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1 Answer

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log(3x) = log(2x-4)

taking antilog of both sides:

3x = 2x - 4

3x - 2x = -4 [subtracting 2x from both sides]

x = -4

and we're done already!

User Yorodm
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