Question

How much energy (in J) is lost when a sample of iron with a mass of 28.3 g cools from 66.0 degrees celsius to 24.0 degrees celsius.

Answer 1

Q = -535 J.

Step-by-step explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the lost energy according to the following and generic heat equation:

`Q=mC(T_F-T_i)`

Thus, since the specific heat of iron is 0.450 in the SI units, we can plug in the mass and temperatures to obtain:

`Q=28.3g*0.450(J)/(g\°C) (24.0\°C-66.0\°C)\\\\Q=-535J`

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