Question

Suppose a normal distribution has a mean of 98 and a standard deviation of 6. What is P(x is greater than or equal to 86)? A. 0.16 B. 0.475 C. 0.84 D. 0.975

Answer 1

0.975 is the probability value

Explanation:

We start by getting the z score of 86

z-score = (x - mean)/SD

z-score = (86-98)/6 = -12/6 = -2

So we want to find the probability of z greater than or equal to 2

We shall be using the standard normal distribution table here

We have the answer as;

0.975