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Three yrs hence, a men will be three time his brother age and the sum of present age is 18 find their present age

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Answer:

Explanation:

Let the age of a man = x

Age of his brother = y

Three yrs hence, a man will be three time his brother age

This is written as:

x + 3 = 3(y + 3)

x + 3 = 3y + 9 .... Equation 1

The sum of present age is 18

= x + y = 18

x = 18 - y

We substitute 18 - y for x in Equation 1

find their present age

18 - y + 3 = 3y + 9

Collect like terms

21 - 9 = 3y + y

12 = 4y

y = 12/4

y = 3 years

x = 18 - y

x = 18 - 3

x = 15 years

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