Answer:
We accept H₀ p₁ = p₂ : We don´t have evidence to support any difference between the proportions
Step-by-step explanation:
Information from Ivan Allen College;
Sample size n₁ = 137
The proportion of students failing
p₁ = 0,283 q₁ = 1 - p₁ q₁ = 1 - 0,283 q₁ = 0,717
Information from College of Computing:
Sample size n₂ = 111
x₂ ( number of students failing ) = 22
The proportion of students failing
p₂ = 0,1981 q₂ = 1 - 0,1981 q₂ = 0,8019
Hypothesis Test:
Null Hypothesis: H₀ p₁ = p₂
Alternative Hypothesis Hₐ p₁ ≠ p₂
Alternative Hypothesis indicates the test is a two-tail test
Choosing a significance level α = 0,05 ( Confidence Interval 95%)
we get from z table z(c) = 1,64
To obtain z(s)
z(s) = ( p₁ - p₂ ) / EED
EED = √(p₁*q₁)/n₁ + p₂*q₂)/n₂
EED = √ (0,283*0,717)/137 + ( 0,1981*0,8019)/111
EED = √ 0,00148 + 0,00143
EED = 0,054
And
z(s) = ( 0,283 - 0,1981 )/ 0,054
z(s) = 1,57
Comparing z(c) and z(s)
z(c) > z(s)
Then z(s) is in the acceptance region for H₀ : We accept H₀