Question

CAN SOMEONE HELP PLEASE???

When a​ car's tire pressure is 30 pounds per square inch​ (psi), it averages mpg of gasoline. If the tire pressure is increased to 35​ psi, the car averages mpg of gasoline. Answer parts ​a) through ​c).

If someone drives an average of 21,000 mi per​ year, how many gallons of gasoline will he save in a year by increasing his tire pressure from 30 to 35​ psi?

If gasoline costs ​$2.00 per​ gallon, how much will he save in a​ year?

Assume that there are about 130 million cars in a country and that these changes are typical of each​ car, how many gallons of gasoline would be saved if all drivers increased their​ cars' tire​ pressure?

Answer 1

Answer: $142

Step-by-step explanation: assume 20miles per gallon.

Then 0.05 gallon per mile.

35psi gives 30/35= 0.85 times the surface on the ground, gives square 0.85^2= 0.73 times more deflection so heatproduction a cycle or at same speed. This gives more fuelconsumption.

I once determined that when driving 50mph/80kmph constant, tires use 25% of the total fuel-consumption.

Higher speed same fuelconsumption by the tires, but more bij the higher speed. But to keep it simple only 50mph.

The fuelconsumption at 30 psi 0.05 gpm, 25% by the rolling resistance is 0.0125mpg. 35psi ,0.73 x0.0125=0.0091gpm.

The windforce stays the same 75% of total is 0.0375mpg+ 0.0091= 0.0466mpg,0.0466gpm/0.05= 93% used of fuel with 35psi then at 30 psi.

So 21000mpj x 0.05gpm= 1050 gallon

21000mpjx 0.466gpm= 979gallon.

Saving 1050-979= 71 gallonx $2= $142

Rounded here and there, and other speeds give other divisions, but to show the idea how to calculate it.

Also if 25% used is right is discussable.

Answer 2

Answer:he will save 100 $

Explanation: