Question

40 % ply tennis 24% plays baseball 58% plays neither. If you pick a student at random what will be the probably plays both sports.

Answer 1

The probability is 0.22

Explanation:

We know that:

40% of the students play tennis

24% of the students play baseball

58% of the students play neither.

If we add these numbers, we get:

40% + 24% + 58% = 122%

Here we should get exactly 100%, but we get more because we are counting some of the students twice, and that happens because some of the students play both sports, so these students are counted in both percentages.

And we can conclude that exactly 122% - 100% = 22% of the students play both sports:

Now, the probability that a randomly picked student plays both sports, is equal to the quotient between the percentage of students that play both sports and the 100%, this is:

p = 22%/100% = 0.22

The probability is 0.22