Answer:
a. 0.2 A
Step-by-step explanation:
Given;
voltage of the battery, V = 12 V
three resistance connected in series, R₁ = 15 Ω, R₂ = 21 Ω, R₃ = 24Ω
The equivalent resistance for series connection is calculated as;
Rt = R₁ + R₂ + R₃
Rt = 15Ω + 21Ω + 24Ω
Rt = 60 Ω
Apply Ohm's law to calculate the current n the circuit;
V = IRt
I = V/Rt
I = 12/60
I = 0.2 A
Therefore, the current in the circuit is 0.2 A