Question

Point B has coordinates ​(5​,2​). The​ x-coordinate of point A is 1. The distance between point A and point B is 5 units. What are the possible coordinates of point​ A?

Answer 1

• Given - two points A( 1 , y ) and B( 5 , 2) ; Distance between A and B = 5 units

• To find - possible coordinates of A

Using Distance formula ,

`\bold{d(AB) = \sqrt{ (x_(2) - x_(1)) {}^(2) + ( y_(2) - y_(1)) {}^(2) } }\\ \\\bold{5 = \sqrt{(5 - 1) {}^(2) + (2 - y) {}^(2) }} \\ \\\bold\blue{ squaring \: both \: sides\:,} \\ \\\bold{ 25 = (5 - 1) {}^(2) + (2 - y) {}^(2) }\\ \\\bold{ 25 = (4) {}^(2) + (4 + y {}^(2) - 4y)}\\ \\ \bold{25 = 16 + y {}^(2) - 4y + 4}\\ \\ \bold{25 = y {}^(2) - 4y + 20}\\ \\\bold{ y {}^(2) - 4y - 5 = 0}\\ \\\bold{ y {}^(2) - 5y + y - 5 = 0} \\\\\bold{ y(y - 5) + 1(y - 5) = 0}\\ \\\bold{ (y + 1)(y - 5) = 0 }\\\\\bold{ y = - 1 \: or \: y = + 5}`

therefore ,

possible coordinates of A are either ( 1 , -1 ) or ( 1 , 5 )

hope helpful~