Question

NEED HELP ASAP 50 POINTS

Rhombus ABCD has a diagonal BD¯¯¯¯¯.

m∠ADB=(4x−12)°

m∠CDB=(3x+6)°

What is the m∠ADC ?

Enter your answer in the box

º

Answer 1

Angle ADC = 7x - 6°

Explanation:

4x - 12 + 3x + 6 = 7x - 6

Answer 2

• 120°

Explanation:

Diagonal BD of a given rhombus is angle bisector of ∠ADC, so:

• m∠ADB = m∠CDB

Substitute the values and solve for x:

• 4x - 12 = 3x + 6
• 4x - 3x = 6 + 12
• x = 18

Find the value of ∠ADC:

• m∠ADC = 2(4*18 - 12) = 120°