Question

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals StartFraction one-fourth EndFraction left-parenthesis x minus 12 right-parenthesis.(x – 12). What is the standard form of the equation for this line?

Answer 1

y = one-fourth x minus three-fourths got it on the edge

Answer 2

Given:

The line passes through the two points (–4, –3) and (12, 1).

The point-slope form of the equation of the line is:

`y-1=(1)/(4)(x-12)`

To find:

The standard form of the equation for this line.

Solution:

The standard form of a line:

`Ax+By=C`

The given point-slope form of the equation of the line is:

`y-1=(1)/(4)(x-12)`

Multiply both sides by 4.

`4(y-1)=(x-12)`

`4y-4=x-12`

`-4+12=x-4y`

`8=x-4y`

Interchanging the sides, we get

`x-4y=8`

Therefore, the standard form of the equation for this line is
`x-4y=8`.