106k views
2 votes
How large a sample should be selected to provide a 95 confidence interval with a margin of error of 10? Assume that the population standard deviation is 40.

User Mihuilk
by
8.2k points

1 Answer

2 votes

Answer:

the required sample size is 62

Explanation:

Given the data in the question;

Confidence interval C = 95% = 0.95

Margin of error E = 10

population standard deviation σ = 40

sample size n = ?

We use the following formula to get our sample size;

sample size n = ( (
Z_c × σ ) / E )²

Next we find z value for confidence interval

Confidence interval C = 95% = 0.95

Area = ( 1 + c )/2 = ( 1 + 0.95)/2 = 1.95 / 2 = 0.975

Now we check our z-table to see the area where 0.975 falls;

It falls under column 0.06 and Row 1.9

so, our z-value for confidence interval of 0.95 is 1.96

so we substitute

sample size n = ( ( 1.96 × 40 ) / 10 )²

n = ( 78.4 / 10 )²

n = ( 7.84 )²

n = 61.4656

we know that sample size is always rounded up, so

n = 62

Therefore, the required sample size is 62

User LemonCool
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories