Question

Please help!!!!!!!!!!!!!!!!!

Answer 1

Hi there!

`\large\boxed{t = 12.60 \text{ days}}`

We can solve this by setting the equation equal to 150:

`150 = (230)/(1 + 56.5e^-0.37t)`

Cross-multiply and divide:

`150 (1 + 56.5e^(-0.37t))= 230`

Divide both sides by 150:

`1 + 56.5e^(-0.37t) = 1.5333`

Isolate for t by subtracting both sides by 1 and dividing by 56.5:

`56.5e^(-0.37t) = 0.5333`

`e^(-0.37t) = 0.0094395`

Take the natural log to solve for t:

`ln (0.0094395) = -0.37t`

`-4.6628522 = -0.37t`

Divide both sides by -0.37:

t = 12.60 days.