Question

Calculate the number of grams in 260 mL ( 1000mL = 1 L) of a 0.55 M solution of NaCl. (1

mol = 58 g)

Answer 1

8.29g NaCl are present

Step-by-step explanation:

To solve this question we must, as first, find the moles of NaCl in 260mL of the solution. These moles can be converted to grams using its molar mass (NaCl = 58g/mol)

Moles NaCl:

260mL * (1L / 1000mL) = 0.260L * (0.55mol / L) = 0.143 moles NaCl

Mass NaCl:

0.143 moles NaCl * (58g / mol) = 8.29g NaCl are present