Question

Please help

The pressure of a 70.0L sample of gas is 600 mm Hg at 20.0°C. If the temperature drops to 15.0"C and the volume expands to 90.0 L, what will the
pressure of the gas be?

Answer 1

"457.2 mm.Hg" is the right solution.

Step-by-step explanation:

Given:

Pressure,

`P_1=600 \ mm.Hg`

`P_2 = ?\\`

Volume,

`V_1=70.0 \ L`

`V_2=90.0 \ L`

Temperature,

`T_1=20^(\circ)`

or,

`=293 \ K`

`T_2=15.0^(\circ)`

or,

`=288 \ K`

As we know,

⇒
`(P_1V_1)/(T_1) =(P_2V_2)/(T_2)`

By putting all the given values in the above expression, we get

⇒
`(0.789* 70)/(293) =(P_2* 90)/(288)`

⇒
`0.188=(P_2* 90)/(288)`

By applying cross-multiplication, we get

⇒
`P_2=(0.188* 288)/(90)`

⇒
`=(54.144)/(90)`

⇒
`=0.6016 \ atm`

or,

⇒
`=457.2 \ mm.Hg`