Question

Tree dies are rolled and the results are shown and multiplied. If the product is an even number, how high is the probability that the sum of those numbers is also even?

Answer 1

Explanation:

If I roll a die three times, what is the probability the product of the three numbers is odd?

If I roll a die three times, what is the probability the product of the three numbers is odd?Once you multiply by an even number, the outcome is guaranteed to be even. So it's the chance that all die are odd.

If I roll a die three times, what is the probability the product of the three numbers is odd?Once you multiply by an even number, the outcome is guaranteed to be even. So it's the chance that all die are odd.The probability that a single die is odd is 1/2 or .5.

If I roll a die three times, what is the probability the product of the three numbers is odd?Once you multiply by an even number, the outcome is guaranteed to be even. So it's the chance that all die are odd.The probability that a single die is odd is 1/2 or .5.To say that “ALL” dice are something, means an AND operation, and AND is the same as multiplication.

If I roll a die three times, what is the probability the product of the three numbers is odd?Once you multiply by an even number, the outcome is guaranteed to be even. So it's the chance that all die are odd.The probability that a single die is odd is 1/2 or .5.To say that “ALL” dice are something, means an AND operation, and AND is the same as multiplication.So the probabilities multiply.

So the solution is

`(1)/(2) * (1)/(2) * (1)/(2) = (1)/(8)`