Answer:
Amplitude of sine wave in volts peak = 2.25 V
Step-by-step explanation:
Given:
Vertical sensitivity control = 0.5 volts per division
Time base control = 2.5 ms per division
Find:
Amplitude of sine wave in volts peak
Computation:
Amplitude of sine wave in volts peak = 4¹/₂[volts per division]
Amplitude of sine wave in volts peak = 4¹/₂[0.5]
Amplitude of sine wave in volts peak = 4.5[0.5]
Amplitude of sine wave in volts peak = 2.25 V