Question

If 20. milliliters of 1.0 M HCl was used to completely neutralize 40. milliliters of an NaOH solution, what was the molarity of the NaOH solution?

A) 0.50 M B) 2.0 M C) 1.5 M D) 4.0 M

Answer 1

To find the molarity of the NaOH solution, you can use the equation: moles of acid = moles of base. The molarity of the NaOH solution is 0.50 M.

Step-by-step explanation:

To find the molarity of the NaOH solution, we can use the equation:

moles of acid = moles of base

First, let's calculate the moles of HCl:

moles of HCl = concentration of HCl * volume of HCl = 1.0 M * 0.020 L = 0.020 moles

Since the equation is a one-to-one ratio, the moles of NaOH will also be 0.020 moles. To calculate the molarity of the NaOH solution:

molarity of NaOH = moles of NaOH / volume of NaOH = 0.020 moles / 0.040 L = 0.50 M

Therefore, the molarity of the NaOH solution is 0.50 M.

Answer 2

a)0.50

Step-by-step explanation:

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