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How many molecules are in 1.28 mols of silicon dioxide​

1 Answer

3 votes

Answer:

7.71x10^23 molecules

Step-by-step explanation:

Avogadro's # = 6.022x10^23

1.28 mol SiO2 x 6.022x10^23/ 1 mol SiO2 = 7.71x10^23 molecules

User Rob Fox
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