Question

Find the coordinates of centroid of a triangle whose vertices have coordinates (6,2);(- 3, 4); (3,- 9).

(- 2,1)
(1, - 2)
(2, - 1)
(- 2, - 1)

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Answer 1

`\huge \bf༆ Answer ༄`

Let's solve ~

According to formula, the coordinates of Centroid of a triangle are ;

`\sf x = (x_1 + x_2 + x_3 )/(3)`

`\sf y = (y_1 + y_2 + y_3 )/(3)`

So, plug the coordinates of its vertices in the formula to find the required solution !

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = (6 + ( - 3) + 3)/(3)`

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = (2+ 4 + (- 9) )/(3)`

Further solving ~

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = (6)/(3)`

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = ( - 3)/(3)`

Therefore, the required coordinates are ~

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 2`

`{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = - 1`

Correct choice is ;

`\overbrace{  \underbrace{\underline{ \boxed{ \sf (2 ,-1)}}}}`