Question

Fe2O3(s) + H2(g) = Fe(s) + H2O(l)

jenny does the experiment above and is able to produce 595 grams of iron. how many liters of hydrogen gas would she need to accomplish this?

Answer 1

Step-by-step explanation:

`molar \: mass \: of \: iron = 56 \: g \\ 56 \: g\: are \: weighed \: by \: 1 \: mole \: of \: iron \\ 595 \: g \: will \: be \: weighed \: by \: ( (595)/(56) ) \: moles \\ = 10.625 \: moles \: of \: iron \\ from \: equation : \\ 1 \: mole \: of \: iron \: is \: formed \: by \: 1 \: mole \: of \: hydrogen \\ 10.625 \: moles \: will \: be \: produced \: by \: (10.625 * 1) \: moles \\ = 10.625 \: moles \: of \: hydrogen \\ at \: s.t.p : \\ 1 \: mole \: = \: 22.4 \: litres \\ 10.625 \: moles \: = (22.4 * 10.625) \\ = 238 \: litres \\ \\ or \: at \: r.t.p : \\ 1 \: mole \: = 24 \: litres \\ 10.625 \: moles \: = \: (10.625 * 24) \\ = 255 \: litres`