What is the [OH-] of a substance that has a pH of 11?

asked Jul 12, 2022 6.9k views

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Answer:

0.001 M OH-

Step-by-step explanation:

[OH-] = 10^-pOH, so

pOH + pH = 14 and 14 - pH = pOH

14 - 11 = 3

[OH⁻] = 10⁻³ ; [OH-] = 0.001 M OH-

Laran Evans answered Jul 16, 2022

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